[Toán 6] Tìm min

T

thaonguyenkmhd

$A=(x-5)^2+(y+3)^2$

Ta có $ (x-5)^2$ \geq 0 và $(y+3)^2$ \geq 0

\Rightarrow $A=(x-5)^2+(y+3)^2$ \geq 0

\Rightarrow min A= 0 khi $\left \{ \begin{array}((x-5)^2=0 \\ (y+3)^2=0 \end{array} \right. \leftrightarrow \left \{ \begin{array}xx=5 \\ y=-3 \end{array} \right.$
 
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