toan 6 so sanh phan so

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harrypham

[TEX]A= \frac{1}{2^2}+ \frac{1}{3^2}+...+\frac{1}{100^2}< \frac{1}{1.2}+ \frac{1}{2.3}+...+ \frac{1}{99.100}= 1 - \frac{1}{100}<1[/TEX].
 
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