[toán 6] khó khó khó khó!

M

mr_cross_fire

Theo đề bài ra ta có:

[TEX]\frac{23+n}{40+n}=\frac{3}{4}[/TEX]

\Rightarrow [TEX]4(23+n)=3(40+n)[/TEX]
\Rightarrow [TEX]92+4n=120+3n[/TEX]
\Rightarrow [TEX]92+n=120[/TEX]
\Rightarrow[TEX] n=28[/TEX]

Vậy [TEX]n=28[/TEX]
 
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