toán 5 - hãy chứng tỏ các phân số =

T

thangvegeta1604

a. $\dfrac{45}{87}=\dfrac{45:3}{87:3}=\dfrac{15}{29}$

$\dfrac{4545}{8787}$=$\dfrac{4545:303}{8787:303}$=$\dfrac{15}{29}$

$\dfrac{454545}{878787}=\dfrac{454545:30303}{878787:30303}=\dfrac{15}{29}$

Vậy $\dfrac{45}{87}$=$\dfrac{4545}{8787}$=$\dfrac{454545}{878787}$
 
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