Toán 12

N

nguyenbahiep1

Gợi ý

[laTEX] sin x - cosx +1 = -\frac{1}{5}(sinx+ 2cosx+3) - \frac{3}{5}(cosx-2sinx) + \frac{8}{5} \\ \\ I = ( -\frac{x}{5} -\frac{3ln|sin x + 2cosx+3|}{5}) \big|_0^{\frac{\pi}{2}} + \frac{8}{5}I_1 \\ \\ I_1 = \int_{0}^{\frac{\pi}{2}}\frac{dx}{sinx+ 2cosx+3} \\ \\ t = tan(\frac{x}{2}) \Rightarrow dt = \frac{1}{2}(1+tan(\frac{x}{2})) \\ \\ sin x = \frac{2t}{1+t^2} \\ \\ cosx = \frac{1-t^2}{1+t^2}[/laTEX]
 
You must log in or register to reply here.
Top Bottom