Toán 12

N

nguyenbahiep1

[TEX]t = x+ \frac{\pi}{3} \Rightarrow x = t - \frac{\pi}{3}\Rightarrow 3x = 3t - \pi\\ 8cos^3t = cos (3t - \pi) \\ 8cos^3t = -cos3t \\ 8cos^3t = 3cost - 4cos^3t \\ 12cos^3t - 3cost = 0 [/TEX]
 
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