[toán 12] tổ hợp

A

anhtuanphan

Tính tổng sau đây :
Tính [TEX]S=\frac{1}{2}C_n^0+\frac{1}{3}C_n^1+...+\frac{1}{n+2}C_n^n[/TEX]
anh chung minh bieu thuc nay nhe
eq.latex

viec con lai la thay k bang 0,1,2,3,...,n roi tinh tong
 
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K

kimxakiem2507

Tính tổng :
[TEX]S=\frac{1}{3}2^nC_n^0+\frac{1}{2}2^{n-1}4C_n^1+2^{n-2}4^2C_n^2+....+\frac{n^2+1}{n+3}4^nC_n^n[/TEX]
 
V

vodichhocmai

Tính tổng :
[TEX]S=\frac{1}{3}2^nC_n^0+\frac{1}{2}2^{n-1}4C_n^1+2^{n-2}4^2C_n^2+....+\frac{n^2+1}{n+3}4^nC_n^n[/TEX]

[TEX]S:=\sum_{k=1}^{n}kC_{n}^k2^{n-k}.4^k -3\sum_{k=0}^{n}C_{n}^k2^{n-k}.4^k+10\sum_{k=0}^{n}\frac{1}{k+3}C_{n}^k2^{n-k}.4^k[/TEX]

[TEX]S:= \sum_{k=1}^{n}kC_{n}^k2^{n-k}.4^k-3\sum_{k=0}^{n}C_{n}^k2^{n-k}.4^k+10\sum_{k=0}^{n}\frac{1}{k+3}C_{n}^k2^{n-k}4^k[/TEX]

[TEX]\tex{S:= dao ham + khai trien binh thuong + tich phan}[/TEX]
 
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