[toán 12] tính tích phân

N

nguyenbahiep1

[laTEX]\int_{0}^{\frac{\pi}{6}} \frac{\sqrt[3]{cosx - cos^3x}}{cos^3x}dx \\ \\ \int_{0}^{\frac{\pi}{6}} \frac{\sqrt[3]{\frac{1}{cos^2x} - 1}}{cos^2x}dx \\ \\ \int_{0}^{\frac{\pi}{6}} \frac{\sqrt[3]{tan^2x}}{cos^2x}dx \\ \\ tan x = u \Rightarrow du = \frac{dx}{cos^2x}[/laTEX]
 
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