[toán 12]tìm nguyên hàm

N

nguyenhanhnt2012

Hù

[TEX]\int\limits{e^xcosx}dx[/TEX]
Đặt u=cosx,[TEX]dv=e^x[/TEX]=>du=?,v=?
[TEX]\Rightarrow\text I=cosx.e^x+\int\limits{e^xsinx}dx[/TEX]
[TEX]\text{I'}=\int\limits{e^xsinxdx} \text{u'=sinx,dv'=e^xdx}\rightarrow\text{du'=?,v=?[/TEX]
[TEX]\text{I'}=sinx.e^x-\int\limits{e^xcosxdx}[/TEX]
[TEX]\rightarrow\text{I}=e^x.(sinx+cosx)-\int\limits{e^x.cosxdx}[/TEX]
[TEX]\rightarrow\text{2I}={e^x.(sinx+cosx)}\rightarrow\text{I}=?[/TEX]
 
You must log in or register to reply here.
Top Bottom