[Toán 12] Tìm nguyên hàm: $\int \frac{(x-1)^2}{(2x+1)^4}dx$

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haichaustudy

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V

vivietnam

$ I=\displaystyle\int (\dfrac{x-1}{2x+1})^2.\frac{1}{(2x+1)^2}dx=\displaystyle \dfrac{1}{3} \int (\dfrac{x-1}{2x+1})^2 d(\dfrac{x-1}{2x+1})=\dfrac{(x-1)^3}{9.(2x+1)^3} $
 
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