[toán 12] tích phân

N

nguyenbahiep1

[laTEX]sin3x = 3sinx - 4sin^3x \Rightarrow sin^3x = \frac{3sinx}{4} -\frac{sin 3x}{4} \\ \\ \frac{1}{4}\int_{0}^{\frac{\pi}{2}} (3sinx - sin 3x)dx = \frac{cos3x}{12}- \frac{3cosx}{4} \big|_0^{\frac{\pi}{2}}[/laTEX]
 
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