[toán 12] tích phân

T

truongduong9083

mình giúp bạn nhé

ta có
[TEX](sinx+cosx)^2=2sin^2(x+\frac{\pi}{4})[/TEX]
nên
[TEX]\int_{}^{}\frac{dx}{(sinx+cosx)^2}=\int_{}^{}\frac{dx}{2sin(x+\frac{\pi}{4})^2}[/TEX]
[TEX]=-\frac{1}{2}cot(x+\frac{\pi}{4})+C[/TEX]
 
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