[Toán 12] - Nguyên hàm

V

vivietnam

$I=\int_0^2 \dfrac{xdx}{x^2-4x+6}$
$I=\int_0^2 \dfrac{d(x^2-4x+6)}{2(x^2-4x+6)}+\int_0^2 \dfrac{2dx}{(x-2)^2+2}$
$I=\dfrac{1}{2} ln|x^2-4x+6||_0^2+\dfrac{arctan\dfrac{x-2}{\sqrt{2}}}{\sqrt{2}}|_0^2=.....$
 
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