[toán 12] hàm số logarit

N

nguyenbahiep1

[laTEX]dk : x > 0 \\ \\ x\not = 4,2, \\ \\ log_2x = u \Rightarrow log_4x = \frac{u}{2} \\ \\ log_2 log_3 \frac{u}{2} = log_4 log_3 u \\ \\ log_3 \frac{u}{2} = \sqrt{log_3 u} \\ \\ log_3 u - log_32 = \sqrt{log_3 u} \\ \\ \sqrt{log_3 u} = t \\ \\ t^2 -t - log_3 2 = 0 [/laTEX]
 
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