[toán 12 ] Giải pt

T

thantai2015

\[\begin{array}{l}
{3^{2x - 10}}{.2^{4x - 20}} = 0 \Leftrightarrow (2x - 10)\ln 3 + (2x - 10)2\ln 2 = 0\\
\Leftrightarrow (2x - 10)(\ln 3 + 2\ln 2) = 0 \Leftrightarrow x = 5
\end{array}\]
 
T

thantai2015

\[\begin{array}{l}
{3^{\sqrt {x - 2} }} - {9^{x - 5}} = 0 \Leftrightarrow {3^{\sqrt {x - 2} }} - {3^{2x - 10}} = 0 \Leftrightarrow \sqrt {x - 2} = 2x - 10\\
x \ge 2 \Rightarrow x - 2 = 4{(x - 5)^2} \Leftrightarrow 4{x^2} - 41x + 102 = 0\\
\Leftrightarrow x = 6 \vee x = 4,25
\end{array}\]
 
T

thantai2015

\[\begin{array}{l}
{3^{x - 1}}{.5^{2x + 3}} = {3^{5x}}{.5^{5x}} \Leftrightarrow {3^{4x + 1}}{.5^{3x - 3}} = 1 \Leftrightarrow (4x + 1)\ln 3 + (3x - 3)\ln 5 = 0\\
\Leftrightarrow (4\ln 3 + 3\ln 5)x + \ln 3 - 3\ln 5 = 0 \Leftrightarrow x = \dfrac{{3\ln 5 - \ln 3}}{{4\ln 3 + 3\ln 5}}
\end{array}\]
 
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