Toán 12 : Cần gấp.. mong mọi ng jup'

A

anhnguyen404

Last edited by a moderator:
K

kimxakiem2507

[TEX]t=(3+2\sqrt2)^{tgx}\ \ x\in{(-\frac{\pi}{2},\frac{\pi}{2})\Rightarrow{t>0[/TEX]
[TEX]pt\Rightarrow{f(t)=t+\frac{1}{t}=m \ \ (t>0)[/TEX]
[TEX]f^'(t)=1-\frac{1}{t^2}\Rightarrow{f^'(t)=0\Leftrightarrow{t=1[/TEX]
[TEX]BBT\Rightarrow{YCBT\Leftrightarrow{m>2[/TEX]
 
Top Bottom