[Toán 11] Tổ hợp xác suất

L

loverain22

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nguyenbahiep1

câu 2

[TEX]\frac{(n-1)!}{4!(n-5)!} - \frac{(n-1)!}{3!(n-4)!} - \frac{5.(n-1)!}{4.2!.(n-3)!} \leq 0 \\ \frac{1}{4!(n-5)!} - \frac{1}{3!(n-4)(n-5)!} - \frac{5}{4.2!.(n-3)(n-4)(n-5)!} \leq 0 \\ \frac{1}{12} - \frac{1}{3(n-4)} - \frac{5}{4(n-3)(n-4)} \leq 0 \\ \frac{4n+3}{n^2-7n +12} \geq 1 [/TEX]
 
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