[Toán 11] Tính tổng

D

datmuicamau

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C

cbeo100kg

Tổng quát là:[TEX] \frac{k}{2^k}.(k+1)![/TEX]
[TEX] \frac{k}{2^k}.(k+1)!\\= \frac{k+2-2}{2^k}.(k+1)!\\=\frac{(k+2)!-2.(k+1)!}{2^k}\\=\frac{(k+2)!}{2^k}-\frac{(k+1)!}{2^(k-1)}[/TEX]

Ta có
[TEX]S= \frac{3!}{2}-\frac{2!}{1}+\frac{4!}{2^2}-\frac{3!}{2}+..........+ \frac{(n+2)!}{2^n}-\frac{(n+1)!}{2^(n-1)}\\= \frac{(n+2)!}{2^n}-\frac{2!}{1}[/TEX]

:D
 
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