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![](https://blog.hocmai.vn/wp-content/uploads/2017/07/hot.gif)
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Các bác cho em hỏi câu nhé:
[TEX]\sqrt2cos(\frac{x}{5}-\frac{\pi}{12}) - \sqrt6sin(\frac{x}{5}-\frac{\pi}{12}) = 2sin(\frac{x}{5} + \frac{2\pi}{3}) - sin(\frac{3x}{5} + \frac{\pi}{6})[/TEX]
[TEX]\sqrt2cos(\frac{x}{5}-\frac{\pi}{12}) - \sqrt6sin(\frac{x}{5}-\frac{\pi}{12}) = 2sin(\frac{x}{5} + \frac{2\pi}{3}) - sin(\frac{3x}{5} + \frac{\pi}{6})[/TEX]