[Toán 11] Lượng giác

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niemkieuloveahbu

[TEX]cos3x-4cos2x+3cosx-4=0\\ \Leftrightarrow 4cos^3x-8cos^2x=0\\ \Leftrightarrow \[cosx=0\\ cosx=2(L) \Rightarrow x=\frac{\pi}{2}+k\pi(k\in Z)[/TEX]

[TEX]x \in [0,14] \Rightarrow x=\frac{\pi}{2},x=\frac{3\pi}{2},x=\frac{5\pi}{2},x=\frac{7\pi}{2}[/TEX]
 
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