[ Toán 11 ] Lim

L

lovelycat_handoi95

[TEX]\blue{\mathrm{Ta\ co\ \\ \frac{3tan^4x-12tanx}{sin4x-12sinx}\\=\frac{3tanx(tan^3x-4)}{4sinx(cosxcos2x-3)}\\=\frac{3tan^3x-12}{4cos^2xcos2x-12cosx}\\=\frac{3sin^3x-12cos^3x}{4cos^5xcos2x-12cos^4x}\\ \Rightarrow \lim_{x \to 0 } \frac{3tan^4x-12tanx}{sin4x-12sinx}\\ = \lim_{x \to 0 } \frac{3sin^3x-12cos^3x}{4cos^5xcos2x-12cos^4x}\\ = \frac{3}{2}[/TEX]
 
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