[Toán 11] giới hạn

S

smileandhappy1995

[TEX]lim_{x\to\infty} \frac{sin^25x}{2x}[/TEX]\leq [TEX]lim_{x\to\infty}\frac{1}{2x}[/TEX]
mà [TEX]lim_{x\to\infty}\frac{1}{2x}=0 [/TEX]\Rightarrow [TEX]lim_{x\to\infty} \frac{sin^25x}{2x}=0[/TEX]
 
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H

hotmitlui2

lim_{x\to...} \frac{sin5x.5.sin5x.5}{5.2x.5}
= lim_{x\to...}\frac{5}{2}.lim\frac{1}{x}
= 0
 
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