câu 5
đk...
$\frac{\sqrt{3}sin2x-cos2x-5sinx+(2-\sqrt{3})cosx+3+\sqrt{3}}{2cosx+\sqrt{3}}=1$
$\leftrightarrow \sqrt{3}sin2x-cos2x-5sinx+(2-\sqrt{3})cosx+3+\sqrt{3}=2cosx+\sqrt{3}$
$\leftrightarrow 2\sqrt{3}sinxcosx-(1-2sin^2x)-5sinx-\sqrt{3}cosx+3=0$
$\leftrightarrow \sqrt{3}cosx(2sinx-1)+(2sin^2x-5sinx+2)=0$
$\leftrightarrow \sqrt{3}cosx(2sinx-1)+(sinx-2)(2sinx-1)=0$
dế rồi nhá em