[toán 11] bt

N

nguyenbahiep1

[TEX](sinx+3)( sin^4 (\frac{x}{2}) - sin^2 (\frac{x}{2}) ) +1 = 0 \\ (sinx+3).sin^2 (\frac{x}{2}). ( -cos^2 (\frac{x}{2})) + 1 = 0 \\ -\frac{1}{4}.(sin x+3).sin^2x +1 = 0 \\ sin^3x +3sin^2x -4 = 0 \\ sin x = 1 \\ sin x = -2 (L)[/TEX]
 
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