S
sweet_love8


giải pt:
1) cosx.cos2x.sin3x = 1/3.sin2x
2) sin2x +cos2x -cosx +3sinx -2 =0
3) 3.tan^2(x -pi/2) = 2[ ( 1-sinx)/ sinx]
4) 1+sinx +cosx + tanx =0
1) cosx.cos2x.sin3x = 1/3.sin2x
2) sin2x +cos2x -cosx +3sinx -2 =0
3) 3.tan^2(x -pi/2) = 2[ ( 1-sinx)/ sinx]
4) 1+sinx +cosx + tanx =0