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1> [TEX] 2sin^3x + 2sin^2x + cosx -1=0 [/TEX]
2>[TEX]\sqrt{3} sin2x - 2cos^2x = 2\sqrt{2}+ 2cos2x[/TEX]
![Confused :confused: :confused:](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
![Confused :confused: :confused:](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
![Confused :confused: :confused:](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
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Chú ý cách đặt tiêu đề
2>[TEX]\sqrt{3} sin2x - 2cos^2x = 2\sqrt{2}+ 2cos2x[/TEX]
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Chú ý cách đặt tiêu đề
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