T
tuyetkhongtan


a/[TEX]2(tan{\frac{x}{2}}-1)=cosx[/TEX]
b/[TEX]sin^4-sin^4(x+\frac{pi}{2})=4sin{\frac{x}{2}}cos{\frac{x}{2}}cosx[/TEX]
c/[TEX]\frac{cos2x+cotg2x+sin4x}{cotg2x-cos2x}=2[/TEX]
d/[TEX]cos6x=2sin(\frac{3\pi}{2}+2x)[/TEX]
e/[TEX]\frac{tgx}{1-tg^2x}-2\sqrt{sinxsin(5 \frac{\pi}{2}+x)}=\frac{1}{2}[/TEX]
b/[TEX]sin^4-sin^4(x+\frac{pi}{2})=4sin{\frac{x}{2}}cos{\frac{x}{2}}cosx[/TEX]
c/[TEX]\frac{cos2x+cotg2x+sin4x}{cotg2x-cos2x}=2[/TEX]
d/[TEX]cos6x=2sin(\frac{3\pi}{2}+2x)[/TEX]
e/[TEX]\frac{tgx}{1-tg^2x}-2\sqrt{sinxsin(5 \frac{\pi}{2}+x)}=\frac{1}{2}[/TEX]
Last edited by a moderator: