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L

locxoaymgk

Cho a>0,b>0 . Chứng minh rằng [tex]ab+\frac{a}{b}+\frac{b}{a} \geq a+b+1[/tex]
Theo BDT cô si :
Ta có: [TEX]ab+\frac{a}{b}\geq 2a[/TEX]

[TEX] ab+\frac{b}{a} \geq 2b.[/TEX]

[TEX] \frac{a}{b}+\frac{b}{a} \geq 2.[/TEX]

Công từng vế ta có:

[TEX]2ab+2\frac{a}{b}+2\frac{b}{a} \geq 2a+2b+2[/TEX]

[TEX] \Rightarrow ab+\frac{a}{b}+\frac{b}{a} \geq a+b+1[/TEX]
 
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