[toán 10]tìm min

T

tuyn

[TEX]A=a+b+c+\frac{1}{a}+\frac{1}{b}+\frac{1}{c} \geq a+b+c+\frac{9}{a+b+c}=[a+b+c+\frac{1}{a+b+c}]+\frac{8}{a+b+c} \geq 2+8=10[/TEX]
\RightarrowMinA=10 khi [TEX]a=b=c=\frac{1}{3}[/TEX]
 
Top Bottom