[Toán 10] Hypebol

N

nguyenbahiep1

giải

$(d): 4x-2y - 8 = 0 \\ \\ y^2 -2y-8 = 0 \\ \\ y = 4, x = 4 \Rightarrow A(4,4) \\ \\ y = -2, x = 1 \Rightarrow B (1,-2) \\ \\ |\overrightarrow{AB}| = 3.\sqrt{5} \\ \\ (d) = (AB): 2x-y-4 = 0 \\ \\ C ( \frac{c^2}{4},c) \\ \\ d(C,(AB)) = \frac{|\frac{c^2}{2}-c-4|}{\sqrt{5}} \\ \\ S_{ABC} = \frac{d(C,(AB)).AB}{2} = 12 \\ \\ |\frac{c^2}{2}-c-4|.3 = 24 \\ \\ |\frac{c^2}{2}-c-4| = 8 $

đến đây đơn giản rồi
 
Last edited by a moderator:
You must log in or register to reply here.
Top Bottom