[Toán 10] HPT

H

hn3

Mệt @-) [TEX]\left{\begin{-y^2+2y+4=\sqrt{x+y}(1)}\\{x-24y=\sqrt{x+y-25}(2)}[/TEX]

[TEX](2)<=>{-25}(y-1)=\sqrt{x+y-25}-(\sqrt{x+y-25})^2[/TEX]

[TEX](1)<=>{-}(y-1)^2+5=\sqrt{x+y}[/TEX]

[TEX]==>{-}[\frac{{-}\sqrt{x+y-25}+(\sqrt{x+y-25})^2}{25}]^2+5=\sqrt{x+y}[/TEX]

Đặt [TEX]u=x+y-25[/TEX] .

....................:|......................... Hướng nào gọn không nhỉ :-/
 
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