L
luantran1997


giải hệ phương trình sau:
[tex]\left\{ \begin{array}{l} 2 + 6y +\sqrt{x-2y} = \frac{x}{y} \\ \sqrt{x+\sqrt{x-2y}} = x+3y-2 \end{array} \right.[/tex]
[tex]\left\{ \begin{array}{l} 2 + 6y +\sqrt{x-2y} = \frac{x}{y} \\ \sqrt{x+\sqrt{x-2y}} = x+3y-2 \end{array} \right.[/tex]
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