H
hyhoha123


giải pt:
[laTEX]\begin{cases} \sqrt{x}+\sqrt{2-y}= \sqrt{2} \\ \sqrt{y}+ \sqrt{2-x} = \sqrt{2} \end{cases}[/laTEX]
[laTEX]\begin{cases} \sqrt{x}+\sqrt{2-y}= \sqrt{2} \\ \sqrt{y}+ \sqrt{2-x} = \sqrt{2} \end{cases}[/laTEX]
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