H
hoanggu95


Giải các PT sau:
1;[TEX]3-x+\sqrt[3]{4-x}=\sqrt{3+x}+\sqrt[3]{1+\sqrt{3+x}}[/TEX]
2;[TEX]6x-{x}^{2}-2=|x-1|+|x-2|+|2x-3|+|4x-13|[/TEX]
thanks

























1;[TEX]3-x+\sqrt[3]{4-x}=\sqrt{3+x}+\sqrt[3]{1+\sqrt{3+x}}[/TEX]
2;[TEX]6x-{x}^{2}-2=|x-1|+|x-2|+|2x-3|+|4x-13|[/TEX]
thanks