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toan10a1


cho hpt sau
[TEX]\left{3y=\frac{y2+2}{x^2}\ \ \\3x=\frac{x^2+2}{y2}\ \ [/TEX]
[TEX]\left{\sqrt[]{x^2+2}+x+\sqrt[]{y^2+3}+y=5\\\sqrt[]{x^2+2}-x+\sqrt[]{y^2+3}-y=2[/TEX]
[TEX]\left{3y=\frac{y2+2}{x^2}\ \ \\3x=\frac{x^2+2}{y2}\ \ [/TEX]
[TEX]\left{\sqrt[]{x^2+2}+x+\sqrt[]{y^2+3}+y=5\\\sqrt[]{x^2+2}-x+\sqrt[]{y^2+3}-y=2[/TEX]
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