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lv_cn_dbk


giải hệ phương trình
[tex]\left\{ \begin{array}{l} x^2+1 +y(x+y)=4y \\ (x^2+1)(x+y-2) = y \end{array} \right.[/tex]
[tex]\left\{ \begin{array}{l} x^2+1 +y(x+y)=4y \\ (x^2+1)(x+y-2) = y \end{array} \right.[/tex]
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