[Toán 10] bất đẳng thức

L

l94

[tex] \frac{a^3}{a+b}+\frac{b^3}{b+c}+\frac{c^3}{c+a} \geq \frac{(a^2+b^2+c^2)^2}{(a^2+b^2+c^2+ab+bc+ca)} \geq\frac{(a^2+b^2+c^2)^2}{2(a^2+b^2+c^2)}=\frac{1}{2}(a^2+b^2+c^2)[/tex]
dấu = xảy ra khi a=b=c
 
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