[Toán 10] Bài tập lượng giác

L

lovelycat_handoi95

[TEX]cot^2 a + tan^2 a = 2cos4a +\frac{6}{1-cos4a}[/TEX]
Cảm ơn các bạn.
đk:[TEX]cos^2x \not= 0,sin^2x \not= 0[/TEX]

[TEX]\Leftrightarrow \frac{sin^4x+cos^4}{sin^2xcos^2x}=2(1-2sin^22x)+\frac{6}{1-(1-2sin^22x)}[/TEX]

[TEX]\Leftrightarrow \frac{2(1-\frac{1}{2}sin^22x)}{sin^22x}=2-4sin^22x+\frac{3}{sin^22X}[/TEX]

[TEX]\Leftrightarrow \frac{-1-sin^22x}{sin^22x}-2+4sin^22x=0[/TEX]

[TEX]\Leftrightarrow 4sin^42x-3sin^22x-1=0[/TEX]

[TEX]\Leftrightarrow \left [sin^2x=1\\sin^2x=\frac{-1}{4}(loai)[/TEX]
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