[Toám 8]Tính giá trị của p

V

vinhthanh1998

[TEX]P=\frac{2009a}{ab+2009a+2009}+\frac{b}{bc+b+2009}+\frac{c}{ac+c+1}[/TEX]
[TEX]P=\frac{a^2bc}{ab+a^2bc+abc}+\frac{b}{bc+b+abc}+ \frac{c}{ac+c+1} [/TEX]
[TEX]P=\frac{a^2bc}{ab(ac+c+1)}+\frac{b}{b(ac+c+1)}+ \frac{c}{ac+c+1} [/TEX]
[TEX]P=\frac{ac}{ac+c+1}+\frac{1}{ac+c+1}+\frac{c}{ac+c+1}[/TEX]
[TEX]P=\frac{ac+c+1}{ac+c+1}[/TEX]
[TEX]P=1[/TEX]

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