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thaiha_98

Tính:[tex]A=\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+...+\frac{1}{120}[/tex]:(
Ta có:
$A=\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+...+ \frac{1}{120}$
\Rightarrow $\frac{A}{2}=\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+...+\frac{1}{240}$
\Rightarrow $\frac{A}{2}=\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{15.16}$
\Rightarrow $\frac{A}{2}=\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{15}-\frac{1}{16}$
\Rightarrow $\frac{A}{2}=\frac{1}{4}-\frac{1}{16}$
\Rightarrow $\frac{A}{2}=\frac{3}{16}$
\Rightarrow $A=\frac{3}{8}$
Vậy...
 
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