tính tích phân

N

nguyenbahiep1

$x\sqrt{3}lnx+1 = u \Rightarrow du = \sqrt{3}(lnx +1)dx \\ \\ I = \int_{1}^{2\sqrt{3}ln2+1} \frac{du}{\sqrt{3}u} = \frac{1}{\sqrt{3}}ln|u| \big|_{1}^{2\sqrt{3}ln2+1} = ?$
 
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