

Cho [tex]a^{3}+b^{3}+c^{3}[/tex] [tex]= 3abc[/tex]
Tính B=[tex]\begin{pmatrix} 1+\frac{a}{b} \end{pmatrix}\begin{pmatrix} 1+\frac{b}{c} \end{pmatrix}\begin{pmatrix} 1+\frac{c}{a} \end{pmatrix}[/tex]
Tính B=[tex]\begin{pmatrix} 1+\frac{a}{b} \end{pmatrix}\begin{pmatrix} 1+\frac{b}{c} \end{pmatrix}\begin{pmatrix} 1+\frac{c}{a} \end{pmatrix}[/tex]