[tex]k=3n\rightarrow sin\left ( \frac{\pi }{6}+2n\pi \right )=sin\frac{\pi }{6}=\frac{1}{2}[/tex]
[tex]k=3n+1\rightarrow sin\left ( \frac{\pi }{6}+\frac{2\pi (3n+1)}{3} \right )=sin\left ( \frac{\pi }{6}+\frac{2\pi}{3}+2n\pi \right )=sin\frac{5\pi }{6}=\frac{1}{2}[/tex]
[tex]k=3n+2\rightarrow sin\left ( \frac{\pi }{6}+\frac{4\pi }{3} \right )=-1[/tex]
Vậy k=3n hoặc k=3n+1 thì sin(...)=1/2; k=3n+2 thì sin(...)=-1