Ta có: [tex]A=\frac{1}{1+\sqrt{2}}+\frac{2}{\sqrt{2}+\sqrt{3}}+...+\frac{99}{\sqrt{99}+\sqrt{100}}=\sqrt{2}-1+2(\sqrt{3}-\sqrt{2})+3(\sqrt{4}-\sqrt{3})+...+99(\sqrt{100}-\sqrt{99})=99\sqrt{100}-\sqrt{99}-\sqrt{98}-...-\sqrt{2}-1\Rightarrow A+B=100\sqrt{100}=1000[/tex]