tinh dao ham

C

cafekd


~O) Giải:

$ y= \sqrt{x\sqrt{x\sqrt{x\sqrt{x}}}} = \sqrt{x\sqrt{x\sqrt{\sqrt{x^3}}}}$

$ = \sqrt{x\sqrt{x\sqrt[4]{x^3}}} = \sqrt{x\sqrt{\sqrt[4]{x^7}}} $

$ = \sqrt{x\sqrt[8]{x^7}} = \sqrt[16]{x^{15}} = x^{\frac{15}{16}}.$

→ $ y' = \frac{15}{16\sqrt[16]{x}}. $



 
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