U
uq235119


moi nguoi giai gium cai cam on nhieuCho hàm số. Đặt
.Khi đó
bằng:![]()
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[TEX]y^'=\frac{1}{\frac{1}{x+1}}.(-\frac{1}{(x+1)^2})=-\frac{1}{x+1}\Rightarrow{S=x.y^'=-\frac{x}{x+1}=\frac{1}{x+1}-1=e^{y}-1[/TEX]
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