(8x-3) (3x+2) - (4x+7) (x+4) = ( 2x+1 ) (5x-1) - 33
(8x-3) (3x+2) - (4x+7) (x+4) = ( 2x+1 ) (5x-1) - 33
<=> [tex]24x^2+16x-9x-6-4x^2-16x-7x-28=10x^2-2x+5x-1-33[/tex]
<=> [tex] 10x^2 -19x=0[/tex]
<=> [tex]x(10x-19)=0[/tex]
<=> x= 0 hoặc x =[tex]\frac{19}{10}[/tex]