Tìm x:x+4/2010 + x+3/2011 = x+2/2012 + x+1/2013
View attachment 109532
(x+4)/2010 + (x+3)/2011 = (x+2)/2012 +(x+1)/2013
<=> (x+2014)/2010 +(x+2014)/2011 = (x+2014)/2012 + (x+2014)/2013 ( cộng vào mỗi bên 2)
[tex](x+2014)(1/2010+1/2011-1/2012-1/2013)=0[/tex]
Vì (1/2010+1/2011-1/2012-1/2013) luôn khác 0
=> x+2014=0
=> x = -2014