Tìm x?

M

manhnguyen0164

$(x^2 -x + 1)^2 = -3x^2 + 3x +1$

Khai triển ra :p rồi thu gọn được:

$\iff x^4-2x^3+6x^2-5x=0$

$\iff (x-1)x(x^2-x+5)=0 \iff \left[\begin{matrix}x-1=0\\x=0\\x^2-x+5=0\end{matrix}\right.$

$\iff \left[\begin{matrix}x=0\\x=1\\(x-\dfrac{1}{2})^2+\dfrac{19}{4}=0\end{matrix}\right. \iff \left[\begin{matrix}x=0\\x=1\end{matrix}\right.$

 
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