Cho : [tex]\frac{x}{3} = \frac{y}{4} = k \Leftrightarrow x = 3k, y = 4k[/tex]
[tex]\frac{z}{5} = \frac{y}{7} = \frac{4k}{7} \Leftrightarrow z = \frac{20k}{7}[/tex]
Nên [tex]2x + 3y - z = 6k + 12k - \frac{20k}{7} = \frac{106k}{7} = 106 \Leftrightarrow k = 7[/tex]
Vậy [tex]x = 3.7 = 21, y = 4.7 = 28, z = \frac{20.7}{7} = 20[/tex]